奇函數(shù)
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滿足:
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,且在區(qū)間
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與
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上分別遞減和遞增,則不等式
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的解集為______________.
奇函數(shù)
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滿足:
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,所以f(3)=0且f(0)=0;f(x)在
區(qū)間
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與
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上分別遞減和遞增,則在區(qū)間[-2,0]與(-∞,-2]分別遞減和遞增;
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;
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故
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解集是
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科目:高中數(shù)學(xué)
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設(shè)奇函數(shù)
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在
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上是增函數(shù),且
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,則不等式
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的解集為
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已知函數(shù)
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(
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且
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)
(1)求
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的定義域和值域
(2)判斷
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的奇偶性,并證明
(3)當(dāng)
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時,若對任意實數(shù)
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,不等式
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恒成立,求實數(shù)
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的取值范圍
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若奇函數(shù)
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在
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,則使得
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已知
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為
R上的減函數(shù),則滿足
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的實數(shù)
x的取值范圍是( )
A.(– 1,1) | B.(0,1) |
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上單調(diào)遞增的( )
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已知函數(shù)
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時,有極大值
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。
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